/* origin: FreeBSD /usr/src/lib/msun/src/e_sqrt.c */
/*
 * ====================================================
 * Copyright (C) 1993 by Sun Microsystems, Inc. All rights reserved.
 *
 * Developed at SunSoft, a Sun Microsystems, Inc. business.
 * Permission to use, copy, modify, and distribute this
 * software is freely granted, provided that this notice
 * is preserved.
 * ====================================================
 */
/* sqrt(x)
 * Return correctly rounded sqrt.
 *           ------------------------------------------
 *           |  Use the hardware sqrt if you have one |
 *           ------------------------------------------
 * Method:
 *   Bit by bit method using integer arithmetic. (Slow, but portable)
 *   1. Normalization
 *      Scale x to y in [1,4) with even powers of 2:
 *      find an integer k such that  1 <= (y=x*2^(2k)) < 4, then
 *              sqrt(x) = 2^k * sqrt(y)
 *   2. Bit by bit computation
 *      Let q  = sqrt(y) truncated to i bit after binary point (q = 1),
 *           i                                                   0
 *                                     i+1         2
 *          s  = 2*q , and      y  =  2   * ( y - q  ).         (1)
 *           i      i            i                 i
 *
 *      To compute q    from q , one checks whether
 *                  i+1       i
 *
 *                            -(i+1) 2
 *                      (q + 2      ) <= y.                     (2)
 *                        i
 *                                                            -(i+1)
 *      If (2) is false, then q   = q ; otherwise q   = q  + 2      .
 *                             i+1   i             i+1   i
 *
 *      With some algebric manipulation, it is not difficult to see
 *      that (2) is equivalent to
 *                             -(i+1)
 *                      s  +  2       <= y                      (3)
 *                       i                i
 *
 *      The advantage of (3) is that s  and y  can be computed by
 *                                    i      i
 *      the following recurrence formula:
 *          if (3) is false
 *
 *          s     =  s  ,       y    = y   ;                    (4)
 *           i+1      i          i+1    i
 *
 *          otherwise,
 *                         -i                     -(i+1)
 *          s     =  s  + 2  ,  y    = y  -  s  - 2             (5)
 *           i+1      i          i+1    i     i
 *
 *      One may easily use induction to prove (4) and (5).
 *      Note. Since the left hand side of (3) contain only i+2 bits,
 *            it does not necessary to do a full (53-bit) comparison
 *            in (3).
 *   3. Final rounding
 *      After generating the 53 bits result, we compute one more bit.
 *      Together with the remainder, we can decide whether the
 *      result is exact, bigger than 1/2ulp, or less than 1/2ulp
 *      (it will never equal to 1/2ulp).
 *      The rounding mode can be detected by checking whether
 *      huge + tiny is equal to huge, and whether huge - tiny is
 *      equal to huge for some floating point number "huge" and "tiny".
 *
 * Special cases:
 *      sqrt(+-0) = +-0         ... exact
 *      sqrt(inf) = inf
 *      sqrt(-ve) = NaN         ... with invalid signal
 *      sqrt(NaN) = NaN         ... with invalid signal for signaling NaN
 */

#include "libm.h"

static const double tiny = 1.0e-300;

double sqrt(double x) {
  double z;
  int32_t sign = (int)0x80000000;
  int32_t ix0, s0, q, m, t, i;
  uint32_t r, t1, s1, ix1, q1;

  EXTRACT_WORDS(ix0, ix1, x);

  /* take care of Inf and NaN */
  if ((ix0 & 0x7ff00000) == 0x7ff00000) {
    return x * x + x; /* sqrt(NaN)=NaN, sqrt(+inf)=+inf, sqrt(-inf)=sNaN */
  }
  /* take care of zero */
  if (ix0 <= 0) {
    if (((ix0 & ~sign) | ix1) == 0)
      return x; /* sqrt(+-0) = +-0 */
    if (ix0 < 0)
      return (x - x) / (x - x); /* sqrt(-ve) = sNaN */
  }
  /* normalize x */
  m = ix0 >> 20;
  if (m == 0) { /* subnormal x */
    while (ix0 == 0) {
      m -= 21;
      ix0 |= (ix1 >> 11);
      ix1 <<= 21;
    }
    for (i = 0; (ix0 & 0x00100000) == 0; i++)
      ix0 <<= 1;
    m -= i - 1;
    ix0 |= ix1 >> (32 - i);
    ix1 <<= i;
  }
  m -= 1023; /* unbias exponent */
  ix0 = (ix0 & 0x000fffff) | 0x00100000;
  if (m & 1) { /* odd m, double x to make it even */
    ix0 += ix0 + ((ix1 & sign) >> 31);
    ix1 += ix1;
  }
  m >>= 1; /* m = [m/2] */

  /* generate sqrt(x) bit by bit */
  ix0 += ix0 + ((ix1 & sign) >> 31);
  ix1 += ix1;
  q = q1 = s0 = s1 = 0; /* [q,q1] = sqrt(x) */
  r = 0x00200000;       /* r = moving bit from right to left */

  while (r != 0) {
    t = s0 + r;
    if (t <= ix0) {
      s0 = t + r;
      ix0 -= t;
      q += r;
    }
    ix0 += ix0 + ((ix1 & sign) >> 31);
    ix1 += ix1;
    r >>= 1;
  }

  r = sign;
  while (r != 0) {
    t1 = s1 + r;
    t = s0;
    if (t < ix0 || (t == ix0 && t1 <= ix1)) {
      s1 = t1 + r;
      if ((t1 & sign) == sign && (s1 & sign) == 0)
        s0++;
      ix0 -= t;
      if (ix1 < t1)
        ix0--;
      ix1 -= t1;
      q1 += r;
    }
    ix0 += ix0 + ((ix1 & sign) >> 31);
    ix1 += ix1;
    r >>= 1;
  }

  /* use floating add to find out rounding direction */
  if ((ix0 | ix1) != 0) {
    z = 1.0 - tiny; /* raise inexact flag */
    if (z >= 1.0) {
      z = 1.0 + tiny;
      if (q1 == (uint32_t)0xffffffff) {
        q1 = 0;
        q++;
      } else if (z > 1.0) {
        if (q1 == (uint32_t)0xfffffffe)
          q++;
        q1 += 2;
      } else
        q1 += q1 & 1;
    }
  }
  ix0 = (q >> 1) + 0x3fe00000;
  ix1 = q1 >> 1;
  if (q & 1)
    ix1 |= sign;
  ix0 += m << 20;
  INSERT_WORDS(z, ix0, ix1);
  return z;
}